The repeating part is what makes them equal. Let us try this one again. If 1/9 is .1(repeating), then 9 * (1/9) is .9(repeating). But 9 * (1/9) is 1. If 9 * (1/9) is equal to 9 * (1/9), which it is, then .9(repeating) is equal to 1.Quote:
Originally Posted by 'spudstar99',index.php?page=Thread&postID=201848#p ost201848
I'll say it again - the REPEATING is what makes them equal. Well, okay. I lied. The repeating is helping me here. What really makes them equal is the transitive property of equality. In English, all I'm saying is that if a=b and a=c, then b=c by definition. Here, a = 9 * (1/9), b = .9(repeating), and c = 1.
.9(repeating) = 1
Question?
EDITED: While correct, the above argument is assuming. Many people aren't going to notice that 1/9 and .1(repeating) can stand in for each other. Because of this, I've assumed a recursive application of the transitive property of equality. I'm going to provide an even more basic argument to clarify.
1/9 = .111(repeating)
Multiply both sides of the equation by 9. (To avoid the assumption of clarity made by my last argument)
9 * (1/9) = 9 * .111(repeating)
The previous line yields this: 1 = .999 (repeating)
Is that more helpful?